m-7(4-3m)=2(6m+6)

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Solution for m-7(4-3m)=2(6m+6) equation: 



m-7(4-3m)=2(6m+6)

We move all terms to the left:

m-7(4-3m)-(2(6m+6))=0

We add all the numbers together, and all the variables

m-7(-3m+4)-(2(6m+6))=0

We multiply parentheses

m+21m-(2(6m+6))-28=0



We calculate terms in parentheses: -(2(6m+6)), so:

2(6m+6)

We multiply parentheses

12m+12

Back to the equation:

-(12m+12)



We add all the numbers together, and all the variables

22m-(12m+12)-28=0

We get rid of parentheses

22m-12m-12-28=0

We add all the numbers together, and all the variables

10m-40=0

We move all terms containing m to the left, all other terms to the right

10m=40

m=40/10

m=4

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