(2x-3)/3=(4-5x)/4

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Solution for (2x-3)/3=(4-5x)/4 equation: 



(2x-3)/3=(4-5x)/4

We move all terms to the left:

(2x-3)/3-((4-5x)/4)=0

We add all the numbers together, and all the variables

(2x-3)/3-((-5x+4)/4)=0

We calculate fractions


2x/()+(-((-5x+4)*3)/()=0



We calculate terms in parentheses: +(-((-5x+4)*3)/(), so:

-((-5x+4)*3)/(

We multiply all the terms by the denominator


-((-5x+4)*3)



We calculate terms in parentheses: -((-5x+4)*3), so:

(-5x+4)*3

We multiply parentheses

-15x+12

Back to the equation:

-(-15x+12)



We get rid of parentheses

15x-12

Back to the equation:

+(15x-12)



We get rid of parentheses

2x/()+15x-12=0

We multiply all the terms by the denominator


2x+15x*()-12*()=0

We add all the numbers together, and all the variables

2x+15x*()=0

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