m+1/2m=15

Solution for m+1/2m=15 equation:

m+1/2m=15

We move all terms to the left:

m+1/2m-(15)=0


Domain of the equation: 2m!=0

m!=0/2

m!=0

m∈R


We multiply all the terms by the denominator


m*2m-15*2m+1=0

Wy multiply elements

2m^2-30m+1=0

a = 2; b = -30; c = +1;
Δ = b2-4ac
Δ = -302-4·2·1
Δ = 892
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{892}=\sqrt{4*223}=\sqrt{4}*\sqrt{223}=2\sqrt{223}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{223}}{2*2}=\frac{30-2\sqrt{223}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{223}}{2*2}=\frac{30+2\sqrt{223}}{4}
$