(X+2)(4-x)=(6-x)(x+2)

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Solution for (X+2)(4-x)=(6-x)(x+2) equation: 



(X+2)(4-X)=(6-X)(X+2)

We move all terms to the left:

(X+2)(4-X)-((6-X)(X+2))=0

We add all the numbers together, and all the variables

(X+2)(-1X+4)-((-1X+6)(X+2))=0

We multiply parentheses ..

(-1X^2+4X-2X+8)-((-1X+6)(X+2))=0



We calculate terms in parentheses: -((-1X+6)(X+2)), so:

(-1X+6)(X+2)

We multiply parentheses ..

(-1X^2-2X+6X+12)

We get rid of parentheses

-1X^2-2X+6X+12

We add all the numbers together, and all the variables

-1X^2+4X+12

Back to the equation:

-(-1X^2+4X+12)



We get rid of parentheses

-1X^2+1X^2+4X-2X-4X+8-12=0

We add all the numbers together, and all the variables

-2X-4=0

We move all terms containing X to the left, all other terms to the right

-2X=4

X=4/-2

X=-2

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