m+(m+3)+(2m)=57

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Solution for m+(m+3)+(2m)=57 equation: 



m+(m+3)+(2m)=57

We move all terms to the left:

m+(m+3)+(2m)-(57)=0

We add all the numbers together, and all the variables

3m+(m+3)-57=0

We get rid of parentheses

3m+m+3-57=0

We add all the numbers together, and all the variables

4m-54=0

We move all terms containing m to the left, all other terms to the right

4m=54

m=54/4

m=13+1/2

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