2(n+1)+1=(n-5)+(-2)

Solution for 2(n+1)+1=(n-5)+(-2) equation:

2(n+1)+1=(n-5)+(-2)

We move all terms to the left:

2(n+1)+1-((n-5)+(-2))=0

We multiply parentheses

2n-((n-5)+(-2))+2+1=0


We calculate terms in parentheses: -((n-5)+(-2)), so:

(n-5)+(-2)

We add all the numbers together, and all the variables

(n-5)-2

We get rid of parentheses

n-5-2

We add all the numbers together, and all the variables

n-7

Back to the equation:

-(n-7)


We add all the numbers together, and all the variables

2n-(n-7)+3=0

We get rid of parentheses

2n-n+7+3=0

We add all the numbers together, and all the variables

n+10=0

We move all terms containing n to the left, all other terms to the right

n=-10