m*m-1=80m=

Solution for m*m-1=80m= equation:

m*m-1=80m=

We move all terms to the left:

m*m-1-(80m)=0

We add all the numbers together, and all the variables

-80m+m*m-1=0

Wy multiply elements

m^2-80m-1=0

a = 1; b = -80; c = -1;
Δ = b2-4ac
Δ = -802-4·1·(-1)
Δ = 6404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6404}=\sqrt{4*1601}=\sqrt{4}*\sqrt{1601}=2\sqrt{1601}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-2\sqrt{1601}}{2*1}=\frac{80-2\sqrt{1601}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+2\sqrt{1601}}{2*1}=\frac{80+2\sqrt{1601}}{2}
$