2/3(7x-3)=5x-3

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Solution for 2/3(7x-3)=5x-3 equation: 



2/3(7x-3)=5x-3

We move all terms to the left:

2/3(7x-3)-(5x-3)=0



Domain of the equation: 3(7x-3)!=0

x∈R



We get rid of parentheses

2/3(7x-3)-5x+3=0

We multiply all the terms by the denominator


-5x*3(7x-3)+3*3(7x-3)+2=0

Wy multiply elements

-15x^2(7+9x(7+2=0

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