m(3m-8)=16

Solution for m(3m-8)=16 equation:

m(3m-8)=16

We move all terms to the left:

m(3m-8)-(16)=0

We multiply parentheses

3m^2-8m-16=0

a = 3; b = -8; c = -16;
Δ = b2-4ac
Δ = -82-4·3·(-16)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-16}{2*3}=\frac{-8}{6}
=-1+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+16}{2*3}=\frac{24}{6}
=4
$