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3x-2+6x=3(3x+5)
We move all terms to the left:
3x-2+6x-(3(3x+5))=0
We add all the numbers together, and all the variables
9x-(3(3x+5))-2=0
We calculate terms in parentheses: -(3(3x+5)), so:We get rid of parentheses
3(3x+5)
We multiply parentheses
9x+15
Back to the equation:
-(9x+15)
9x-9x-15-2=0
We add all the numbers together, and all the variables
-17!=0
There is no solution for this equation
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