((2x-7)/4)-((1-x)/6)=17

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Solution for ((2x-7)/4)-((1-x)/6)=17 equation:



((2x-7)/4)-((1-x)/6)=17
We move all terms to the left:
((2x-7)/4)-((1-x)/6)-(17)=0
We add all the numbers together, and all the variables
((2x-7)/4)-((-1x+1)/6)-17=0
We calculate fractions
(12x-42)/()+(4x-4)/()-17=0
We multiply all the terms by the denominator
(12x-42)+(4x-4)-17*()=0
We add all the numbers together, and all the variables
(12x-42)+(4x-4)=0
We get rid of parentheses
12x+4x-42-4=0
We add all the numbers together, and all the variables
16x-46=0
We move all terms containing x to the left, all other terms to the right
16x=46
x=46/16
x=2+7/8

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