log(4x)+log(2x+1)=31

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Solution for log(4x)+log(2x+1)=31 equation:


Simplifying
log(4x) + log(2x + 1) = 31

Remove parenthesis around (4x)
glo * 4x + log(2x + 1) = 31

Reorder the terms for easier multiplication:
4glo * x + log(2x + 1) = 31

Multiply glo * x
4glox + log(2x + 1) = 31

Reorder the terms:
4glox + glo(1 + 2x) = 31
4glox + (1 * glo + 2x * glo) = 31
4glox + (1glo + 2glox) = 31

Reorder the terms:
1glo + 4glox + 2glox = 31

Combine like terms: 4glox + 2glox = 6glox
1glo + 6glox = 31

Solving
1glo + 6glox = 31

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-31 + 1glo + 6glox = 31 + -31

Combine like terms: 31 + -31 = 0
-31 + 1glo + 6glox = 0

The solution to this equation could not be determined.

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