x+(x+1)+(x+2)+(x+3)=3

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Solution for x+(x+1)+(x+2)+(x+3)=3 equation:


Simplifying
x + (x + 1) + (x + 2) + (x + 3) = 3

Reorder the terms:
x + (1 + x) + (x + 2) + (x + 3) = 3

Remove parenthesis around (1 + x)
x + 1 + x + (x + 2) + (x + 3) = 3

Reorder the terms:
x + 1 + x + (2 + x) + (x + 3) = 3

Remove parenthesis around (2 + x)
x + 1 + x + 2 + x + (x + 3) = 3

Reorder the terms:
x + 1 + x + 2 + x + (3 + x) = 3

Remove parenthesis around (3 + x)
x + 1 + x + 2 + x + 3 + x = 3

Reorder the terms:
1 + 2 + 3 + x + x + x + x = 3

Combine like terms: 1 + 2 = 3
3 + 3 + x + x + x + x = 3

Combine like terms: 3 + 3 = 6
6 + x + x + x + x = 3

Combine like terms: x + x = 2x
6 + 2x + x + x = 3

Combine like terms: 2x + x = 3x
6 + 3x + x = 3

Combine like terms: 3x + x = 4x
6 + 4x = 3

Solving
6 + 4x = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 4x = 3 + -6

Combine like terms: 6 + -6 = 0
0 + 4x = 3 + -6
4x = 3 + -6

Combine like terms: 3 + -6 = -3
4x = -3

Divide each side by '4'.
x = -0.75

Simplifying
x = -0.75

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