ln(y)=ln(x+1)+c

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Solution for ln(y)=ln(x+1)+c equation: 


Simplifying
ln(y) = ln(x + 1) + c

Multiply ln * y
lny = ln(x + 1) + c

Reorder the terms:
lny = ln(1 + x) + c
lny = (1 * ln + x * ln) + c
lny = (1ln + lnx) + c

Reorder the terms:
lny = c + 1ln + lnx

Solving
lny = c + 1ln + lnx

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1ln' to each side of the equation.
-1ln + lny = c + 1ln + -1ln + lnx

Combine like terms: 1ln + -1ln = 0
-1ln + lny = c + 0 + lnx
-1ln + lny = c + lnx

Add '-1lnx' to each side of the equation.
-1ln + -1lnx + lny = c + lnx + -1lnx

Combine like terms: lnx + -1lnx = 0
-1ln + -1lnx + lny = c + 0
-1ln + -1lnx + lny = c

Reorder the terms:
-1c + -1ln + -1lnx + lny = c + -1c

Combine like terms: c + -1c = 0
-1c + -1ln + -1lnx + lny = 0

The solution to this equation could not be determined.

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