8(1+c)=7(c-4)

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Solution for 8(1+c)=7(c-4) equation:


Simplifying
8(1 + c) = 7(c + -4)
(1 * 8 + c * 8) = 7(c + -4)
(8 + 8c) = 7(c + -4)

Reorder the terms:
8 + 8c = 7(-4 + c)
8 + 8c = (-4 * 7 + c * 7)
8 + 8c = (-28 + 7c)

Solving
8 + 8c = -28 + 7c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7c' to each side of the equation.
8 + 8c + -7c = -28 + 7c + -7c

Combine like terms: 8c + -7c = 1c
8 + 1c = -28 + 7c + -7c

Combine like terms: 7c + -7c = 0
8 + 1c = -28 + 0
8 + 1c = -28

Add '-8' to each side of the equation.
8 + -8 + 1c = -28 + -8

Combine like terms: 8 + -8 = 0
0 + 1c = -28 + -8
1c = -28 + -8

Combine like terms: -28 + -8 = -36
1c = -36

Divide each side by '1'.
c = -36

Simplifying
c = -36

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