k2=9/4

Solution for k2=9/4 equation:

k2=9/4

We move all terms to the left:

k2-(9/4)=0

We add all the numbers together, and all the variables

k2-(+9/4)=0

We add all the numbers together, and all the variables

k^2-(+9/4)=0

We get rid of parentheses

k^2-9/4=0

We multiply all the terms by the denominator


k^2*4-9=0

Wy multiply elements

4k^2-9=0

a = 4; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·4·(-9)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*4}=\frac{-12}{8}
=-1+1/2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*4}=\frac{12}{8}
=1+1/2
$