k2=225k2=225k

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Solution for k2=225k2=225k equation: 



k2=225k^2=225k

We move all terms to the left:

k2-(225k^2)=0

determiningTheFunctionDomain
-225k^2+k2=0

We add all the numbers together, and all the variables

-224k^2=0

a = -224; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-224)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{-448}=0$

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