2(4k-3)=6(k+3)+6k

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Solution for 2(4k-3)=6(k+3)+6k equation: 



2(4k-3)=6(k+3)+6k

We move all terms to the left:

2(4k-3)-(6(k+3)+6k)=0

We multiply parentheses

8k-(6(k+3)+6k)-6=0



We calculate terms in parentheses: -(6(k+3)+6k), so:

6(k+3)+6k

We add all the numbers together, and all the variables

6k+6(k+3)

We multiply parentheses

6k+6k+18

We add all the numbers together, and all the variables

12k+18

Back to the equation:

-(12k+18)



We get rid of parentheses

8k-12k-18-6=0

We add all the numbers together, and all the variables

-4k-24=0

We move all terms containing k to the left, all other terms to the right

-4k=24

k=24/-4

k=-6

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