k/7+3-2(k)=-3

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Solution for k/7+3-2(k)=-3 equation: 



k/7+3-2(k)=-3

We move all terms to the left:

k/7+3-2(k)-(-3)=0

We add all the numbers together, and all the variables

-2k+k/7+6=0

We multiply all the terms by the denominator


-2k*7+k+6*7=0

We add all the numbers together, and all the variables

k-2k*7+42=0

Wy multiply elements

k-14k+42=0

We add all the numbers together, and all the variables

-13k+42=0

We move all terms containing k to the left, all other terms to the right

-13k=-42

k=-42/-13

k=3+3/13

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