2(m+3)-6=-4(m+3)+6

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Solution for 2(m+3)-6=-4(m+3)+6 equation: 



2(m+3)-6=-4(m+3)+6

We move all terms to the left:

2(m+3)-6-(-4(m+3)+6)=0

We multiply parentheses

2m-(-4(m+3)+6)+6-6=0



We calculate terms in parentheses: -(-4(m+3)+6), so:

-4(m+3)+6

We multiply parentheses

-4m-12+6

We add all the numbers together, and all the variables

-4m-6

Back to the equation:

-(-4m-6)



We add all the numbers together, and all the variables

2m-(-4m-6)=0

We get rid of parentheses

2m+4m+6=0

We add all the numbers together, and all the variables

6m+6=0

We move all terms containing m to the left, all other terms to the right

6m=-6

m=-6/6

m=-1

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