k-3(3k-3)=33

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Solution for k-3(3k-3)=33 equation: 



k-3(3k-3)=33

We move all terms to the left:

k-3(3k-3)-(33)=0

We multiply parentheses

k-9k+9-33=0

We add all the numbers together, and all the variables

-8k-24=0

We move all terms containing k to the left, all other terms to the right

-8k=24

k=24/-8

k=-3

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