1/2(18z+20)=4(2z+3)

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Solution for 1/2(18z+20)=4(2z+3) equation:



1/2(18z+20)=4(2z+3)
We move all terms to the left:
1/2(18z+20)-(4(2z+3))=0
Domain of the equation: 2(18z+20)!=0
z∈R
We multiply all the terms by the denominator
-((4(2z+3)))*2(18z+20)+1=0
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20
We calculate terms in parentheses: -((4(2z+3)))*2(18z+20), so:
(4(2z+3)))*2(18z+20

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