1/9(a+3)=1/8(8-a)

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Solution for 1/9(a+3)=1/8(8-a) equation: 



1/9(a+3)=1/8(8-a)

We move all terms to the left:

1/9(a+3)-(1/8(8-a))=0



Domain of the equation: 9(a+3)!=0

a∈R





Domain of the equation: 8(8-a))!=0

a∈R



We add all the numbers together, and all the variables

1/9(a+3)-(1/8(-1a+8))=0

We calculate fractions


(8a(-)/(9(a+3)*8(-1a+8)))+(-9aa/(9(a+3)*8(-1a+8)))=0



We calculate terms in parentheses: +(8a(-)/(9(a+3)*8(-1a+8))), so:

8a(-)/(9(a+3)*8(-1a+8))

We add all the numbers together, and all the variables

8a0/(9(a+3)*8(-1a+8))

We multiply all the terms by the denominator


8a0

We add all the numbers together, and all the variables

8a

Back to the equation:

+(8a)





We calculate terms in parentheses: +(-9aa/(9(a+3)*8(-1a+8))), so:

-9aa/(9(a+3)*8(-1a+8))

We multiply all the terms by the denominator


-9aa

Back to the equation:

+(-9aa)



We get rid of parentheses

8a-9aa=0

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