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3(y-2)=9y+2-2(-2y-4)
We move all terms to the left:
3(y-2)-(9y+2-2(-2y-4))=0
We multiply parentheses
3y-(9y+2-2(-2y-4))-6=0
We calculate terms in parentheses: -(9y+2-2(-2y-4)), so:We get rid of parentheses
9y+2-2(-2y-4)
determiningTheFunctionDomain 9y-2(-2y-4)+2
We multiply parentheses
9y+4y+8+2
We add all the numbers together, and all the variables
13y+10
Back to the equation:
-(13y+10)
3y-13y-10-6=0
We add all the numbers together, and all the variables
-10y-16=0
We move all terms containing y to the left, all other terms to the right
-10y=16
y=16/-10
y=-1+3/5
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