j+20=2/3(2j+20)

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Solution for j+20=2/3(2j+20) equation: 



j+20=2/3(2j+20)

We move all terms to the left:

j+20-(2/3(2j+20))=0



Domain of the equation: 3(2j+20))!=0

j∈R



We multiply all the terms by the denominator


j*3(2j+20))-(2+20*3(2j+20))=0

Wy multiply elements

3j^2(2+60j(2=0

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