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4x-(2x-3)=x+(x+3)
We move all terms to the left:
4x-(2x-3)-(x+(x+3))=0
We get rid of parentheses
4x-2x-(x+(x+3))+3=0
We calculate terms in parentheses: -(x+(x+3)), so:We add all the numbers together, and all the variables
x+(x+3)
We get rid of parentheses
x+x+3
We add all the numbers together, and all the variables
2x+3
Back to the equation:
-(2x+3)
2x-(2x+3)+3=0
We get rid of parentheses
2x-2x-3+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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