j(j+56)=180

Solution for j(j+56)=180 equation:

j(j+56)=180

We move all terms to the left:

j(j+56)-(180)=0

We multiply parentheses

j^2+56j-180=0

a = 1; b = 56; c = -180;
Δ = b2-4ac
Δ = 562-4·1·(-180)
Δ = 3856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3856}=\sqrt{16*241}=\sqrt{16}*\sqrt{241}=4\sqrt{241}$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-4\sqrt{241}}{2*1}=\frac{-56-4\sqrt{241}}{2}
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+4\sqrt{241}}{2*1}=\frac{-56+4\sqrt{241}}{2}
$