-3(z-4)-2(3z+1)=-8

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Solution for -3(z-4)-2(3z+1)=-8 equation: 



-3(z-4)-2(3z+1)=-8

We move all terms to the left:

-3(z-4)-2(3z+1)-(-8)=0

We add all the numbers together, and all the variables

-3(z-4)-2(3z+1)+8=0

We multiply parentheses

-3z-6z+12-2+8=0

We add all the numbers together, and all the variables

-9z+18=0

We move all terms containing z to the left, all other terms to the right

-9z=-18

z=-18/-9

z=+2

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