g.3(1-3g)=-6

Solution for g.3(1-3g)=-6 equation:

g.3(1-3g)=-6

We move all terms to the left:

g.3(1-3g)-(-6)=0

We add all the numbers together, and all the variables

g.3(-3g+1)-(-6)=0

We add all the numbers together, and all the variables

g.3(-3g+1)+6=0

We multiply parentheses

-3g^2+g+6=0

a = -3; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·(-3)·6
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{73}}{2*-3}=\frac{-1-\sqrt{73}}{-6}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{73}}{2*-3}=\frac{-1+\sqrt{73}}{-6}
$