6+10(n-3)=8(n-2)

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Solution for 6+10(n-3)=8(n-2) equation: 



6+10(n-3)=8(n-2)

We move all terms to the left:

6+10(n-3)-(8(n-2))=0

We multiply parentheses

10n-(8(n-2))-30+6=0



We calculate terms in parentheses: -(8(n-2)), so:

8(n-2)

We multiply parentheses

8n-16

Back to the equation:

-(8n-16)



We add all the numbers together, and all the variables

10n-(8n-16)-24=0

We get rid of parentheses

10n-8n+16-24=0

We add all the numbers together, and all the variables

2n-8=0

We move all terms containing n to the left, all other terms to the right

2n=8

n=8/2

n=4

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