g+12=32/g=22

Solution for g+12=32/g=22 equation:

g+12=32/g=22

We move all terms to the left:

g+12-(32/g)=0


Domain of the equation: g)!=0

g!=0/1

g!=0

g∈R


We add all the numbers together, and all the variables

g-(+32/g)+12=0

We get rid of parentheses

g-32/g+12=0

We multiply all the terms by the denominator


g*g+12*g-32=0

We add all the numbers together, and all the variables

12g+g*g-32=0

Wy multiply elements

g^2+12g-32=0

a = 1; b = 12; c = -32;
Δ = b2-4ac
Δ = 122-4·1·(-32)
Δ = 272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{272}=\sqrt{16*17}=\sqrt{16}*\sqrt{17}=4\sqrt{17}$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{17}}{2*1}=\frac{-12-4\sqrt{17}}{2}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{17}}{2*1}=\frac{-12+4\sqrt{17}}{2}
$