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-10x-1/5(50x+50)=-10x+5-10
We move all terms to the left:
-10x-1/5(50x+50)-(-10x+5-10)=0
Domain of the equation: 5(50x+50)!=0We add all the numbers together, and all the variables
x∈R
-10x-1/5(50x+50)-(-10x-5)=0
We get rid of parentheses
-10x-1/5(50x+50)+10x+5=0
We multiply all the terms by the denominator
-10x*5(50x+50)+10x*5(50x+50)+5*5(50x+50)-1=0
Wy multiply elements
-50x^2(5+50x^2(5+25x(5-1=0
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