g+(2+g)+(g-1)=12

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Solution for g+(2+g)+(g-1)=12 equation: 



g+(2+g)+(g-1)=12

We move all terms to the left:

g+(2+g)+(g-1)-(12)=0

We add all the numbers together, and all the variables

g+(g+2)+(g-1)-12=0

We get rid of parentheses

g+g+g+2-1-12=0

We add all the numbers together, and all the variables

3g-11=0

We move all terms containing g to the left, all other terms to the right

3g=11

g=11/3

g=3+2/3

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