(4-r)(6+r)=40

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Solution for (4-r)(6+r)=40 equation: 



(4-r)(6+r)=40

We move all terms to the left:

(4-r)(6+r)-(40)=0

We add all the numbers together, and all the variables

(-1r+4)(r+6)-40=0

We multiply parentheses ..

(-1r^2-6r+4r+24)-40=0

We get rid of parentheses

-1r^2-6r+4r+24-40=0

We add all the numbers together, and all the variables

-1r^2-2r-16=0

a = -1; b = -2; c = -16;
Δ = b2-4ac
Δ = -22-4·(-1)·(-16)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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