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x in (-oo:+oo)
f = (1/3)*(g+h-k) // - (1/3)*(g+h-k)
f-((1/3)*(g+h-k)) = 0
(-1/3)*(g+h-k)+f = 0
f-1/3*(g+h-k) = 0
f-1/3*(g+h-k) = 0
f-1/3*g-1/3*h+1/3*k = 0
f-1/3*g-1/3*h+1/3*k = 0
x belongs to the empty set
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