7(x-4)+12=3(x-2)+4x

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Solution for 7(x-4)+12=3(x-2)+4x equation:


Simplifying
7(x + -4) + 12 = 3(x + -2) + 4x

Reorder the terms:
7(-4 + x) + 12 = 3(x + -2) + 4x
(-4 * 7 + x * 7) + 12 = 3(x + -2) + 4x
(-28 + 7x) + 12 = 3(x + -2) + 4x

Reorder the terms:
-28 + 12 + 7x = 3(x + -2) + 4x

Combine like terms: -28 + 12 = -16
-16 + 7x = 3(x + -2) + 4x

Reorder the terms:
-16 + 7x = 3(-2 + x) + 4x
-16 + 7x = (-2 * 3 + x * 3) + 4x
-16 + 7x = (-6 + 3x) + 4x

Combine like terms: 3x + 4x = 7x
-16 + 7x = -6 + 7x

Add '-7x' to each side of the equation.
-16 + 7x + -7x = -6 + 7x + -7x

Combine like terms: 7x + -7x = 0
-16 + 0 = -6 + 7x + -7x
-16 = -6 + 7x + -7x

Combine like terms: 7x + -7x = 0
-16 = -6 + 0
-16 = -6

Solving
-16 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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