f(-3)=3(-3)-(-3)2+2

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Solution for f(-3)=3(-3)-(-3)2+2 equation: 



f(-3)=3(-3)-(-3)2+2

We move all terms to the left:

f(-3)-(3(-3)-(-3)2+2)=0

We add all the numbers together, and all the variables

f(-3)+1=0

We multiply parentheses

-3f+1=0

We move all terms containing f to the left, all other terms to the right

-3f=-1

f=-1/-3

f=1/3

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