7-(2x+3)=3/4(4x-8)

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Solution for 7-(2x+3)=3/4(4x-8) equation: 



7-(2x+3)=3/4(4x-8)

We move all terms to the left:

7-(2x+3)-(3/4(4x-8))=0



Domain of the equation: 4(4x-8))!=0

x∈R



We get rid of parentheses

-2x-(3/4(4x-8))-3+7=0

We multiply all the terms by the denominator


-2x*4(4x-8))-(3-3*4(4x-8))+7*4(4x-8))=0

We add all the numbers together, and all the variables

-2x*4(4x-8))-(3-3*4(4x-8))+7*4(4x=0

Wy multiply elements

-8x^2(4-48x^2(4=0

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