f(-2)=-2(2)+10

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Solution for f(-2)=-2(2)+10 equation: 



f(-2)=-2(2)+10

We move all terms to the left:

f(-2)-(-2(2)+10)=0

We add all the numbers together, and all the variables

f(-2)-(-12)=0

We add all the numbers together, and all the variables

f(-2)+12=0

We multiply parentheses

-2f+12=0

We move all terms containing f to the left, all other terms to the right

-2f=-12

f=-12/-2

f=+6

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