(8x-4)/6=(-10)

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Solution for (8x-4)/6=(-10) equation: 



(8x-4)/6=(-10)

We move all terms to the left:

(8x-4)/6-((-10))=0

We add all the numbers together, and all the variables

(8x-4)/6+10=0

We multiply all the terms by the denominator


(8x-4)+10*6=0

We add all the numbers together, and all the variables

(8x-4)+60=0

We get rid of parentheses

8x-4+60=0

We add all the numbers together, and all the variables

8x+56=0

We move all terms containing x to the left, all other terms to the right

8x=-56

x=-56/8

x=-7

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