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(((x^1)/3)*(x^2-25))'The calculation above is a derivative of the function f (x)

((x^1)/3)'*(x^2-25)+((x^1)/3)*(x^2-25)'

(((x^1)'*3-(x^1*(3)'))/(3^2))*(x^2-25)+((x^1)/3)*(x^2-25)'

((1*x^(1-1)*3-(x^1*(3)'))/(3^2))*(x^2-25)+((x^1)/3)*(x^2-25)'

((1*3-(x^1*(3)'))/(3^2))*(x^2-25)+((x^1)/3)*(x^2-25)'

((1*3-(x^1*0))/(3^2))*(x^2-25)+((x^1)/3)*(x^2-25)'

1/3*(x^2-25)+((x^1)/3)*(x^2-25)'

1/3*(x^2-25)+((x^1)/3)*((x^2)'+(-25)')

1/3*(x^2-25)+((x^1)/3)*(2*x^(2-1)+(-25)')

1/3*(x^2-25)+((x^1)/3)*(2*x+0)

1/3*(x^2-25)+((x^1)/3)*2*x

(1/3)*(x^2-25)+(2*x^2)/3

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