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((1/(-0.2))*ln(x/300))'The calculation above is a derivative of the function f (x)

(1/(-0.2))'*ln(x/300)+(1/(-0.2))*(ln(x/300))'

0*ln(x/300)+(1/(-0.2))*(ln(x/300))'

0*ln(x/300)+(1/(-0.2))*(1/(x/300))*(x/300)'

0*ln(x/300)+(1/(-0.2))*(1/(x/300))*(((x)'*300-(x*(300)'))/(300^2))

0*ln(x/300)+(1/(-0.2))*(1/(x/300))*((1*300-(x*(300)'))/(300^2))

0*ln(x/300)+(1/(-0.2))*(1/(x/300))*((1*300-(x*0))/(300^2))

0*ln(x/300)+(1/(-0.2))*x^-1

-5*x^-1

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