d2=1.3

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Solution for d2=1.3 equation:



d2=1.3
We move all terms to the left:
d2-(1.3)=0
We add all the numbers together, and all the variables
d^2-1.3=0
a = 1; b = 0; c = -1.3;
Δ = b2-4ac
Δ = 02-4·1·(-1.3)
Δ = 5.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{5.2}}{2*1}=\frac{0-\sqrt{5.2}}{2} =-\frac{\sqrt{}}{2} $
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{5.2}}{2*1}=\frac{0+\sqrt{5.2}}{2} =\frac{\sqrt{}}{2} $

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