2(k+6)+3=4(k+2)+k+1

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Solution for 2(k+6)+3=4(k+2)+k+1 equation: 



2(k+6)+3=4(k+2)+k+1

We move all terms to the left:

2(k+6)+3-(4(k+2)+k+1)=0

We multiply parentheses

2k-(4(k+2)+k+1)+12+3=0



We calculate terms in parentheses: -(4(k+2)+k+1), so:

4(k+2)+k+1

We add all the numbers together, and all the variables

k+4(k+2)+1

We multiply parentheses

k+4k+8+1

We add all the numbers together, and all the variables

5k+9

Back to the equation:

-(5k+9)



We add all the numbers together, and all the variables

2k-(5k+9)+15=0

We get rid of parentheses

2k-5k-9+15=0

We add all the numbers together, and all the variables

-3k+6=0

We move all terms containing k to the left, all other terms to the right

-3k=-6

k=-6/-3

k=+2

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