d(d-2)-3=d(d+1)

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Solution for d(d-2)-3=d(d+1) equation:



d(d-2)-3=d(d+1)
We move all terms to the left:
d(d-2)-3-(d(d+1))=0
We multiply parentheses
d^2-2d-(d(d+1))-3=0
We calculate terms in parentheses: -(d(d+1)), so:
d(d+1)
We multiply parentheses
d^2+d
Back to the equation:
-(d^2+d)
We get rid of parentheses
d^2-d^2-2d-d-3=0
We add all the numbers together, and all the variables
-3d-3=0
We move all terms containing d to the left, all other terms to the right
-3d=3
d=3/-3
d=-1

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