3-2(n-1)=3(n-5)

Solution for 3-2(n-1)=3(n-5) equation:

3-2(n-1)=3(n-5)

We move all terms to the left:

3-2(n-1)-(3(n-5))=0

We multiply parentheses

-2n-(3(n-5))+2+3=0


We calculate terms in parentheses: -(3(n-5)), so:

3(n-5)

We multiply parentheses

3n-15

Back to the equation:

-(3n-15)


We add all the numbers together, and all the variables

-2n-(3n-15)+5=0

We get rid of parentheses

-2n-3n+15+5=0

We add all the numbers together, and all the variables

-5n+20=0

We move all terms containing n to the left, all other terms to the right

-5n=-20

n=-20/-5

n=+4