3x(3x-12)=-36

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Solution for 3x(3x-12)=-36 equation: 



3x(3x-12)=-36

We move all terms to the left:

3x(3x-12)-(-36)=0

We add all the numbers together, and all the variables

3x(3x-12)+36=0

We multiply parentheses

9x^2-36x+36=0

a = 9; b = -36; c = +36;
Δ = b2-4ac
Δ = -362-4·9·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{36}{18}=2$

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