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5(2c+1)-6(c+2)=43
We move all terms to the left:
5(2c+1)-6(c+2)-(43)=0
We multiply parentheses
10c-6c+5-12-43=0
We add all the numbers together, and all the variables
4c-50=0
We move all terms containing c to the left, all other terms to the right
4c=50
c=50/4
c=12+1/2
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