c=(4-3c)-2=0

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Solution for c=(4-3c)-2=0 equation: 



c=(4-3c)-2=0

We move all terms to the left:

c-((4-3c)-2)=0

We add all the numbers together, and all the variables

c-((-3c+4)-2)=0



We calculate terms in parentheses: -((-3c+4)-2), so:

(-3c+4)-2

We get rid of parentheses

-3c+4-2

We add all the numbers together, and all the variables

-3c+2

Back to the equation:

-(-3c+2)



We get rid of parentheses

c+3c-2=0

We add all the numbers together, and all the variables

4c-2=0

We move all terms containing c to the left, all other terms to the right

4c=2

c=2/4

c=1/2

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