(-3-2)+4(1-x)=9(2x-5)-3(3x-5)

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Solution for (-3-2)+4(1-x)=9(2x-5)-3(3x-5) equation: 



(-3-2)+4(1-x)=9(2x-5)-3(3x-5)

We move all terms to the left:

(-3-2)+4(1-x)-(9(2x-5)-3(3x-5))=0

We add all the numbers together, and all the variables

4(-1x+1)-(9(2x-5)-3(3x-5))+(-5)=0

We add all the numbers together, and all the variables

4(-1x+1)-(9(2x-5)-3(3x-5))-5=0

We multiply parentheses

-4x-(9(2x-5)-3(3x-5))+4-5=0



We calculate terms in parentheses: -(9(2x-5)-3(3x-5)), so:

9(2x-5)-3(3x-5)

We multiply parentheses

18x-9x-45+15

We add all the numbers together, and all the variables

9x-30

Back to the equation:

-(9x-30)



We add all the numbers together, and all the variables

-4x-(9x-30)-1=0

We get rid of parentheses

-4x-9x+30-1=0

We add all the numbers together, and all the variables

-13x+29=0

We move all terms containing x to the left, all other terms to the right

-13x=-29

x=-29/-13

x=2+3/13

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